3.2629 \(\int \frac {5-x}{(3+2 x)^{7/2} (2+5 x+3 x^2)^{5/2}} \, dx\)

Optimal. Leaf size=256 \[ -\frac {2 (47 x+37)}{5 (2 x+3)^{5/2} \left (3 x^2+5 x+2\right )^{3/2}}+\frac {215096 \sqrt {3 x^2+5 x+2}}{15625 \sqrt {2 x+3}}+\frac {258536 \sqrt {3 x^2+5 x+2}}{3125 (2 x+3)^{3/2}}+\frac {87144 \sqrt {3 x^2+5 x+2}}{625 (2 x+3)^{5/2}}+\frac {4 (2013 x+1858)}{25 (2 x+3)^{5/2} \sqrt {3 x^2+5 x+2}}+\frac {129268 \sqrt {3} \sqrt {-3 x^2-5 x-2} F\left (\sin ^{-1}\left (\sqrt {3} \sqrt {x+1}\right )|-\frac {2}{3}\right )}{3125 \sqrt {3 x^2+5 x+2}}-\frac {107548 \sqrt {3} \sqrt {-3 x^2-5 x-2} E\left (\sin ^{-1}\left (\sqrt {3} \sqrt {x+1}\right )|-\frac {2}{3}\right )}{15625 \sqrt {3 x^2+5 x+2}} \]

[Out]

-2/5*(37+47*x)/(3+2*x)^(5/2)/(3*x^2+5*x+2)^(3/2)+4/25*(1858+2013*x)/(3+2*x)^(5/2)/(3*x^2+5*x+2)^(1/2)-107548/1
5625*EllipticE(3^(1/2)*(1+x)^(1/2),1/3*I*6^(1/2))*(-3*x^2-5*x-2)^(1/2)*3^(1/2)/(3*x^2+5*x+2)^(1/2)+129268/3125
*EllipticF(3^(1/2)*(1+x)^(1/2),1/3*I*6^(1/2))*(-3*x^2-5*x-2)^(1/2)*3^(1/2)/(3*x^2+5*x+2)^(1/2)+87144/625*(3*x^
2+5*x+2)^(1/2)/(3+2*x)^(5/2)+258536/3125*(3*x^2+5*x+2)^(1/2)/(3+2*x)^(3/2)+215096/15625*(3*x^2+5*x+2)^(1/2)/(3
+2*x)^(1/2)

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Rubi [A]  time = 0.19, antiderivative size = 256, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 6, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.207, Rules used = {822, 834, 843, 718, 424, 419} \[ -\frac {2 (47 x+37)}{5 (2 x+3)^{5/2} \left (3 x^2+5 x+2\right )^{3/2}}+\frac {215096 \sqrt {3 x^2+5 x+2}}{15625 \sqrt {2 x+3}}+\frac {258536 \sqrt {3 x^2+5 x+2}}{3125 (2 x+3)^{3/2}}+\frac {87144 \sqrt {3 x^2+5 x+2}}{625 (2 x+3)^{5/2}}+\frac {4 (2013 x+1858)}{25 (2 x+3)^{5/2} \sqrt {3 x^2+5 x+2}}+\frac {129268 \sqrt {3} \sqrt {-3 x^2-5 x-2} F\left (\sin ^{-1}\left (\sqrt {3} \sqrt {x+1}\right )|-\frac {2}{3}\right )}{3125 \sqrt {3 x^2+5 x+2}}-\frac {107548 \sqrt {3} \sqrt {-3 x^2-5 x-2} E\left (\sin ^{-1}\left (\sqrt {3} \sqrt {x+1}\right )|-\frac {2}{3}\right )}{15625 \sqrt {3 x^2+5 x+2}} \]

Antiderivative was successfully verified.

[In]

Int[(5 - x)/((3 + 2*x)^(7/2)*(2 + 5*x + 3*x^2)^(5/2)),x]

[Out]

(-2*(37 + 47*x))/(5*(3 + 2*x)^(5/2)*(2 + 5*x + 3*x^2)^(3/2)) + (4*(1858 + 2013*x))/(25*(3 + 2*x)^(5/2)*Sqrt[2
+ 5*x + 3*x^2]) + (87144*Sqrt[2 + 5*x + 3*x^2])/(625*(3 + 2*x)^(5/2)) + (258536*Sqrt[2 + 5*x + 3*x^2])/(3125*(
3 + 2*x)^(3/2)) + (215096*Sqrt[2 + 5*x + 3*x^2])/(15625*Sqrt[3 + 2*x]) - (107548*Sqrt[3]*Sqrt[-2 - 5*x - 3*x^2
]*EllipticE[ArcSin[Sqrt[3]*Sqrt[1 + x]], -2/3])/(15625*Sqrt[2 + 5*x + 3*x^2]) + (129268*Sqrt[3]*Sqrt[-2 - 5*x
- 3*x^2]*EllipticF[ArcSin[Sqrt[3]*Sqrt[1 + x]], -2/3])/(3125*Sqrt[2 + 5*x + 3*x^2])

Rule 419

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(1*EllipticF[ArcSin[Rt[-(d/c),
2]*x], (b*c)/(a*d)])/(Sqrt[a]*Sqrt[c]*Rt[-(d/c), 2]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] &
& GtQ[a, 0] &&  !(NegQ[b/a] && SimplerSqrtQ[-(b/a), -(d/c)])

Rule 424

Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[(Sqrt[a]*EllipticE[ArcSin[Rt[-(d/c)
, 2]*x], (b*c)/(a*d)])/(Sqrt[c]*Rt[-(d/c), 2]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[
a, 0]

Rule 718

Int[((d_.) + (e_.)*(x_))^(m_)/Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2], x_Symbol] :> Dist[(2*Rt[b^2 - 4*a*c, 2]
*(d + e*x)^m*Sqrt[-((c*(a + b*x + c*x^2))/(b^2 - 4*a*c))])/(c*Sqrt[a + b*x + c*x^2]*((2*c*(d + e*x))/(2*c*d -
b*e - e*Rt[b^2 - 4*a*c, 2]))^m), Subst[Int[(1 + (2*e*Rt[b^2 - 4*a*c, 2]*x^2)/(2*c*d - b*e - e*Rt[b^2 - 4*a*c,
2]))^m/Sqrt[1 - x^2], x], x, Sqrt[(b + Rt[b^2 - 4*a*c, 2] + 2*c*x)/(2*Rt[b^2 - 4*a*c, 2])]], x] /; FreeQ[{a, b
, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[2*c*d - b*e, 0] && EqQ[m^2, 1/4]

Rule 822

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp
[((d + e*x)^(m + 1)*(f*(b*c*d - b^2*e + 2*a*c*e) - a*g*(2*c*d - b*e) + c*(f*(2*c*d - b*e) - g*(b*d - 2*a*e))*x
)*(a + b*x + c*x^2)^(p + 1))/((p + 1)*(b^2 - 4*a*c)*(c*d^2 - b*d*e + a*e^2)), x] + Dist[1/((p + 1)*(b^2 - 4*a*
c)*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^m*(a + b*x + c*x^2)^(p + 1)*Simp[f*(b*c*d*e*(2*p - m + 2) + b^2*e^2
*(p + m + 2) - 2*c^2*d^2*(2*p + 3) - 2*a*c*e^2*(m + 2*p + 3)) - g*(a*e*(b*e - 2*c*d*m + b*e*m) - b*d*(3*c*d -
b*e + 2*c*d*p - b*e*p)) + c*e*(g*(b*d - 2*a*e) - f*(2*c*d - b*e))*(m + 2*p + 4)*x, x], x], x] /; FreeQ[{a, b,
c, d, e, f, g, m}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && LtQ[p, -1] && (IntegerQ[m] ||
IntegerQ[p] || IntegersQ[2*m, 2*p])

Rule 834

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Sim
p[((e*f - d*g)*(d + e*x)^(m + 1)*(a + b*x + c*x^2)^(p + 1))/((m + 1)*(c*d^2 - b*d*e + a*e^2)), x] + Dist[1/((m
+ 1)*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p*Simp[(c*d*f - f*b*e + a*e*g)*(m + 1)
+ b*(d*g - e*f)*(p + 1) - c*(e*f - d*g)*(m + 2*p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] &&
NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && LtQ[m, -1] && (IntegerQ[m] || IntegerQ[p] || IntegersQ
[2*m, 2*p])

Rule 843

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Dis
t[g/e, Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p, x], x] + Dist[(e*f - d*g)/e, Int[(d + e*x)^m*(a + b*x + c*x^
2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0]
&&  !IGtQ[m, 0]

Rubi steps

\begin {align*} \int \frac {5-x}{(3+2 x)^{7/2} \left (2+5 x+3 x^2\right )^{5/2}} \, dx &=-\frac {2 (37+47 x)}{5 (3+2 x)^{5/2} \left (2+5 x+3 x^2\right )^{3/2}}-\frac {2}{15} \int \frac {1362+1269 x}{(3+2 x)^{7/2} \left (2+5 x+3 x^2\right )^{3/2}} \, dx\\ &=-\frac {2 (37+47 x)}{5 (3+2 x)^{5/2} \left (2+5 x+3 x^2\right )^{3/2}}+\frac {4 (1858+2013 x)}{25 (3+2 x)^{5/2} \sqrt {2+5 x+3 x^2}}+\frac {4}{75} \int \frac {28953+30195 x}{(3+2 x)^{7/2} \sqrt {2+5 x+3 x^2}} \, dx\\ &=-\frac {2 (37+47 x)}{5 (3+2 x)^{5/2} \left (2+5 x+3 x^2\right )^{3/2}}+\frac {4 (1858+2013 x)}{25 (3+2 x)^{5/2} \sqrt {2+5 x+3 x^2}}+\frac {87144 \sqrt {2+5 x+3 x^2}}{625 (3+2 x)^{5/2}}-\frac {8 \int \frac {-147870-\frac {294111 x}{2}}{(3+2 x)^{5/2} \sqrt {2+5 x+3 x^2}} \, dx}{1875}\\ &=-\frac {2 (37+47 x)}{5 (3+2 x)^{5/2} \left (2+5 x+3 x^2\right )^{3/2}}+\frac {4 (1858+2013 x)}{25 (3+2 x)^{5/2} \sqrt {2+5 x+3 x^2}}+\frac {87144 \sqrt {2+5 x+3 x^2}}{625 (3+2 x)^{5/2}}+\frac {258536 \sqrt {2+5 x+3 x^2}}{3125 (3+2 x)^{3/2}}+\frac {16 \int \frac {\frac {1187847}{4}+\frac {872559 x}{4}}{(3+2 x)^{3/2} \sqrt {2+5 x+3 x^2}} \, dx}{28125}\\ &=-\frac {2 (37+47 x)}{5 (3+2 x)^{5/2} \left (2+5 x+3 x^2\right )^{3/2}}+\frac {4 (1858+2013 x)}{25 (3+2 x)^{5/2} \sqrt {2+5 x+3 x^2}}+\frac {87144 \sqrt {2+5 x+3 x^2}}{625 (3+2 x)^{5/2}}+\frac {258536 \sqrt {2+5 x+3 x^2}}{3125 (3+2 x)^{3/2}}+\frac {215096 \sqrt {2+5 x+3 x^2}}{15625 \sqrt {3+2 x}}-\frac {32 \int \frac {-\frac {546237}{4}+\frac {725949 x}{8}}{\sqrt {3+2 x} \sqrt {2+5 x+3 x^2}} \, dx}{140625}\\ &=-\frac {2 (37+47 x)}{5 (3+2 x)^{5/2} \left (2+5 x+3 x^2\right )^{3/2}}+\frac {4 (1858+2013 x)}{25 (3+2 x)^{5/2} \sqrt {2+5 x+3 x^2}}+\frac {87144 \sqrt {2+5 x+3 x^2}}{625 (3+2 x)^{5/2}}+\frac {258536 \sqrt {2+5 x+3 x^2}}{3125 (3+2 x)^{3/2}}+\frac {215096 \sqrt {2+5 x+3 x^2}}{15625 \sqrt {3+2 x}}-\frac {161322 \int \frac {\sqrt {3+2 x}}{\sqrt {2+5 x+3 x^2}} \, dx}{15625}+\frac {193902 \int \frac {1}{\sqrt {3+2 x} \sqrt {2+5 x+3 x^2}} \, dx}{3125}\\ &=-\frac {2 (37+47 x)}{5 (3+2 x)^{5/2} \left (2+5 x+3 x^2\right )^{3/2}}+\frac {4 (1858+2013 x)}{25 (3+2 x)^{5/2} \sqrt {2+5 x+3 x^2}}+\frac {87144 \sqrt {2+5 x+3 x^2}}{625 (3+2 x)^{5/2}}+\frac {258536 \sqrt {2+5 x+3 x^2}}{3125 (3+2 x)^{3/2}}+\frac {215096 \sqrt {2+5 x+3 x^2}}{15625 \sqrt {3+2 x}}-\frac {\left (107548 \sqrt {3} \sqrt {-2-5 x-3 x^2}\right ) \operatorname {Subst}\left (\int \frac {\sqrt {1+\frac {2 x^2}{3}}}{\sqrt {1-x^2}} \, dx,x,\frac {\sqrt {6+6 x}}{\sqrt {2}}\right )}{15625 \sqrt {2+5 x+3 x^2}}+\frac {\left (129268 \sqrt {3} \sqrt {-2-5 x-3 x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+\frac {2 x^2}{3}}} \, dx,x,\frac {\sqrt {6+6 x}}{\sqrt {2}}\right )}{3125 \sqrt {2+5 x+3 x^2}}\\ &=-\frac {2 (37+47 x)}{5 (3+2 x)^{5/2} \left (2+5 x+3 x^2\right )^{3/2}}+\frac {4 (1858+2013 x)}{25 (3+2 x)^{5/2} \sqrt {2+5 x+3 x^2}}+\frac {87144 \sqrt {2+5 x+3 x^2}}{625 (3+2 x)^{5/2}}+\frac {258536 \sqrt {2+5 x+3 x^2}}{3125 (3+2 x)^{3/2}}+\frac {215096 \sqrt {2+5 x+3 x^2}}{15625 \sqrt {3+2 x}}-\frac {107548 \sqrt {3} \sqrt {-2-5 x-3 x^2} E\left (\sin ^{-1}\left (\sqrt {3} \sqrt {1+x}\right )|-\frac {2}{3}\right )}{15625 \sqrt {2+5 x+3 x^2}}+\frac {129268 \sqrt {3} \sqrt {-2-5 x-3 x^2} F\left (\sin ^{-1}\left (\sqrt {3} \sqrt {1+x}\right )|-\frac {2}{3}\right )}{3125 \sqrt {2+5 x+3 x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.51, size = 229, normalized size = 0.89 \[ \frac {2 \left (3871728 x^6+36155064 x^5+129381052 x^4+231620622 x^3+220795962 x^2-2 (2 x+3)^2 \left (3 x^2+5 x+2\right ) \left (53774 \left (3 x^2+5 x+2\right )+70064 \sqrt {5} \sqrt {\frac {x+1}{2 x+3}} \sqrt {\frac {3 x+2}{2 x+3}} (2 x+3)^{3/2} F\left (\sin ^{-1}\left (\frac {\sqrt {\frac {5}{3}}}{\sqrt {2 x+3}}\right )|\frac {3}{5}\right )+26887 \sqrt {5} \sqrt {\frac {x+1}{2 x+3}} \sqrt {\frac {3 x+2}{2 x+3}} (2 x+3)^{3/2} E\left (\sin ^{-1}\left (\frac {\sqrt {\frac {5}{3}}}{\sqrt {2 x+3}}\right )|\frac {3}{5}\right )\right )[phone] x+20514383\right )}{15625 (2 x+3)^{5/2} \left (3 x^2+5 x+2\right )^{3/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(5 - x)/((3 + 2*x)^(7/2)*(2 + 5*x + 3*x^2)^(5/2)),x]

[Out]

(2*(20514383 + 106756189*x + 220795962*x^2 + 231620622*x^3 + 129381052*x^4 + 36155064*x^5 + 3871728*x^6 - 2*(3
+ 2*x)^2*(2 + 5*x + 3*x^2)*(53774*(2 + 5*x + 3*x^2) + 26887*Sqrt[5]*Sqrt[(1 + x)/(3 + 2*x)]*(3 + 2*x)^(3/2)*S
qrt[(2 + 3*x)/(3 + 2*x)]*EllipticE[ArcSin[Sqrt[5/3]/Sqrt[3 + 2*x]], 3/5] + 70064*Sqrt[5]*Sqrt[(1 + x)/(3 + 2*x
)]*(3 + 2*x)^(3/2)*Sqrt[(2 + 3*x)/(3 + 2*x)]*EllipticF[ArcSin[Sqrt[5/3]/Sqrt[3 + 2*x]], 3/5])))/(15625*(3 + 2*
x)^(5/2)*(2 + 5*x + 3*x^2)^(3/2))

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fricas [F]  time = 0.76, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {\sqrt {3 \, x^{2} + 5 \, x + 2} \sqrt {2 \, x + 3} {\left (x - 5\right )}}{432 \, x^{10} + 4752 \, x^{9} + 23256 \, x^{8} + 66656 \, x^{7} + 123867 \, x^{6} + 155895 \, x^{5} + 134543 \, x^{4} + 78609 \, x^{3} + 29754 \, x^{2} + 6588 \, x + 648}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((5-x)/(3+2*x)^(7/2)/(3*x^2+5*x+2)^(5/2),x, algorithm="fricas")

[Out]

integral(-sqrt(3*x^2 + 5*x + 2)*sqrt(2*x + 3)*(x - 5)/(432*x^10 + 4752*x^9 + 23256*x^8 + 66656*x^7 + 123867*x^
6 + 155895*x^5 + 134543*x^4 + 78609*x^3 + 29754*x^2 + 6588*x + 648), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int -\frac {x - 5}{{\left (3 \, x^{2} + 5 \, x + 2\right )}^{\frac {5}{2}} {\left (2 \, x + 3\right )}^{\frac {7}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((5-x)/(3+2*x)^(7/2)/(3*x^2+5*x+2)^(5/2),x, algorithm="giac")

[Out]

integrate(-(x - 5)/((3*x^2 + 5*x + 2)^(5/2)*(2*x + 3)^(7/2)), x)

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maple [B]  time = 0.03, size = 494, normalized size = 1.93 \[ \frac {2 \sqrt {3 x^{2}+5 x +2}\, \left (19358640 x^{6}[phone] x^{5}+322644 \sqrt {15}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, \sqrt {2 x +3}\, x^{4} \EllipticE \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )+1616376 \sqrt {15}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, \sqrt {2 x +3}\, x^{4} \EllipticF \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )[phone] x^{4}+1505672 \sqrt {15}\, \sqrt {2 x +3}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, x^{3} \EllipticE \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )+7543088 \sqrt {15}\, \sqrt {2 x +3}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, x^{3} \EllipticF \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )[phone] x^{3}+2554265 \sqrt {15}\, \sqrt {2 x +3}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, x^{2} \EllipticE \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )[phone] \sqrt {15}\, \sqrt {2 x +3}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, x^{2} \EllipticF \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )[phone] x^{2}+1855203 \sqrt {15}\, \sqrt {2 x +3}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, x \EllipticE \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )+9294162 \sqrt {15}\, \sqrt {2 x +3}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, x \EllipticF \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )[phone] x +483966 \sqrt {2 x +3}\, \sqrt {15}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, \EllipticE \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )+2424564 \sqrt {2 x +3}\, \sqrt {15}\, \sqrt {-2 x -2}\, \sqrt {-30 x -20}\, \EllipticF \left (\frac {\sqrt {30 x +45}}{5}, \frac {\sqrt {15}}{3}\right )[phone]\right )}{78125 \left (2 x +3\right )^{\frac {5}{2}} \left (3 x +2\right )^{2} \left (x +1\right )^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5-x)/(2*x+3)^(7/2)/(3*x^2+5*x+2)^(5/2),x)

[Out]

2/78125*(3*x^2+5*x+2)^(1/2)*(322644*15^(1/2)*EllipticE(1/5*(30*x+45)^(1/2),1/3*15^(1/2))*x^4*(-2*x-2)^(1/2)*(-
30*x-20)^(1/2)*(2*x+3)^(1/2)+1616376*15^(1/2)*EllipticF(1/5*(30*x+45)^(1/2),1/3*15^(1/2))*x^4*(-2*x-2)^(1/2)*(
-30*x-20)^(1/2)*(2*x+3)^(1/2)+1505672*15^(1/2)*EllipticE(1/5*(30*x+45)^(1/2),1/3*15^(1/2))*x^3*(2*x+3)^(1/2)*(
-2*x-2)^(1/2)*(-30*x-20)^(1/2)+7543088*15^(1/2)*EllipticF(1/5*(30*x+45)^(1/2),1/3*15^(1/2))*x^3*(2*x+3)^(1/2)*
(-2*x-2)^(1/2)*(-30*x-20)^(1/2)+2554265*15^(1/2)*EllipticE(1/5*(30*x+45)^(1/2),1/3*15^(1/2))*x^2*(2*x+3)^(1/2)
*(-2*x-2)^(1/2)*(-30*x-20)^(1/2)[phone]*15^(1/2)*EllipticF(1/5*(30*x+45)^(1/2),1/3*15^(1/2))*x^2*(2*x+3)^(1/
2)*(-2*x-2)^(1/2)*(-30*x-20)^(1/2)+1855203*15^(1/2)*EllipticE(1/5*(30*x+45)^(1/2),1/3*15^(1/2))*x*(2*x+3)^(1/2
)*(-2*x-2)^(1/2)*(-30*x-20)^(1/2)+9294162*15^(1/2)*EllipticF(1/5*(30*x+45)^(1/2),1/3*15^(1/2))*x*(2*x+3)^(1/2)
*(-2*x-2)^(1/2)*(-30*x-20)^(1/2)[phone]*x^6+483966*(2*x+3)^(1/2)*15^(1/2)*(-2*x-2)^(1/2)*(-30*x-20)^(1/2)*El
lipticE(1/5*(30*x+45)^(1/2),1/3*15^(1/2))+2424564*(2*x+3)^(1/2)*15^(1/2)*(-2*x-2)^(1/2)*(-30*x-20)^(1/2)*Ellip
ticF(1/5*(30*x+45)^(1/2),1/3*15^(1/2))[phone]*x^5+646905260*x^4+1158103110*x^3+1103979810*x^2+533780945*x+1
02571915)/(2*x+3)^(5/2)/(3*x+2)^2/(x+1)^2

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\int \frac {x - 5}{{\left (3 \, x^{2} + 5 \, x + 2\right )}^{\frac {5}{2}} {\left (2 \, x + 3\right )}^{\frac {7}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((5-x)/(3+2*x)^(7/2)/(3*x^2+5*x+2)^(5/2),x, algorithm="maxima")

[Out]

-integrate((x - 5)/((3*x^2 + 5*x + 2)^(5/2)*(2*x + 3)^(7/2)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ -\int \frac {x-5}{{\left (2\,x+3\right )}^{7/2}\,{\left (3\,x^2+5\,x+2\right )}^{5/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(x - 5)/((2*x + 3)^(7/2)*(5*x + 3*x^2 + 2)^(5/2)),x)

[Out]

-int((x - 5)/((2*x + 3)^(7/2)*(5*x + 3*x^2 + 2)^(5/2)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((5-x)/(3+2*x)**(7/2)/(3*x**2+5*x+2)**(5/2),x)

[Out]

Timed out

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